PS 130, The Parkside School

After we create our script, we are going to draw storyboards to plan how our video shots will look.

For an explanation of how to make your storyboards effective download this document: PS 130 Storyboarding Guide.

Also, here is a template for building a story using storyboards: Creating your Storyboards

Here are some examples of other peoples’ storyboards — look for how they use wide shots, mid shots and close ups to tell their stories:

* working at a desk (3 shots)

* multiple samples

* a cowboy fight (many shots)

* wrestling for a toaster (many shots)

Activities:

1. Let’s watch the PS 124 3-307 video illustration and create storyboards for their 3 shots.

2. Everyone draw 3 ‘frames’ that look like TV screens on a blank sheet of paper, and draw 3 shots that tell the story you wrote in your 3 sentence script.

Fellow P.S. 130 bloggers! We’ve been working on writing about our problem solving and our thinking about the process. We’ll soon be posting our work on the school blog to hopefully receive some feedback on how we did. We decided to attach the problem we worked on and the rubric we used to evaluate how we did in case you’d like to look at them when commenting on our work. So when you have a chance, please read over one or more of our posts and let the mathematicians know what they did well and what could be improved or was unclearly explained. We’ll appreciate your comments to help us become better math communicators.

Looking forward to hearing from you all out there!

4-501 Mathematicians

a-fishy-dilemma.doc
mathrubric1.pdf

Amar-My theory about what the answer should be for a fishy dilemma is 0-36. First, I did a diagram and used numbers. Next, I tried to use a chart with tallies. After, I realised that I can do either addition and multiplication. Finally, my answer was all the numbers, 0-36. My theory was right.

Michael-My theory of the answer was 0-36. First, I read the store for the problem. A t first ,i thought it was easy but it was not. Second, I tried to understand that no one could cach more than 3 fish. Next, I got the answers 4 and 3 and i got 12.Then i said 12 times 3 is 36 so thats how I got my answer.

Sujana-My theory was that the answer is about 25. First, I did 3 boats and 4 people in each boat. Next I tried to give everybody 3 fishes and it worked. After I realized that how about if some people got 0, 1, 2 or 3 fishes. Finally I knew that the answer had to be numbers 0- 36 becausethe hightest number of fish people can get is 36, and the lowest is 0.

Felicidad-My theory about the answer for the fishy dilemma was that it would be below 50. First, I did some multiplying a chart the chart  was coulmns in a row. Next, I tried putting explanations in so it made more sense and it did make more sense because you knew what the numbers ment. After, I realized because I did all the  the number work and used a chart like Dr.Math so I didn’t have to change anything. Finally, my answer was zero through thirty-six because of all the multiplication combinations.

Aldin-My theory about the answer for fishy delemma was the answer would be 32. First, I  found out that there was 12 people. Next,I tried to do adding to get my answer. But it did not work. After,I relized I need to use times tables.Finally,my answer was from 0to 36.

Claudia-My theory about what the answer shoud be around 20. First, I started drawing a picture. I drew 3 circles for a boat.I drew 4 little circlws in each boat. Iattached 3 lines to  the little circel.I got 36.Next,I started thinking about the maxximun and minimun.The maxximun was,36.The minimun was 0. After I realized, that what if some people did not catch fish. Finely, my answer was 0 – 36.  My theory was not correct.

Kayla-My theroy about the anser is 30. First,I did try to sketch out the little fishes and 3 boats with 4 people in each boat, butI did not give out the fishes to each person because if I give out the fishes it will not be the same amout so that each person can get the same thing. Next with my partners is to do like a table and that me and my partners did is  make  groups(group 1 and group 2 and group 3 which means boats). After, I relized that I can put fishes for each group and I put 3 in each group. And then each person got 3 groups for each boat and I started to count by 3′s 3 times and got the number 12. Finally, my anser was 12*3=36 because there woatsere 3 groups of fishes each boat and I counted by 12′s 3 times. I got the number 12 and the numeber 3 from the boats.

Sumaiya-My theory was this problem is going to be easy but it was hard First, I drew 3 boats and 4 people in each boat. Second, I tried multipacation. I multiply 4 times 3 it equals to 12 and then I multiply 12*3=36 . Third, I realized that the answer must be 0-36 and I drew tally marks in the chart.  Finally, I found my answer using these steps.

Sammy-My theory about the answer is 3-06 First, I drew 4 boats then 3 in each boats each person caught 3 fish. Next, I tried to count it all up and I got 36. Next, I count all of it thats how I got 36 After I realized I should use a little bit more muiltplication. Finally, my answer is 36 and the minmium is 0.

Enrique-My theory was first to draw about three boats and in each boat I drew four persons in each boat. Second,I tried to add but it didnt work. Then I used multipacation I kept on doing it then I estimated I said 29. but when I imagind that  each person got a fish and then what drew was what I imagind.Then I counted twelve 3 times and I told the teacher if it was 36 and it was.